4*[ln(5x)+1]=0

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Solution for 4*[ln(5x)+1]=0 equation:


Simplifying
4[ln(5x) + 1] = 0

Remove parenthesis around (5x)
4[ln * 5x + 1] = 0

Reorder the terms for easier multiplication:
4[5ln * x + 1] = 0

Multiply ln * x
4[5lnx + 1] = 0

Reorder the terms:
4[1 + 5lnx] = 0
[1 * 4 + 5lnx * 4] = 0
[4 + 20lnx] = 0

Solving
4 + 20lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 20lnx = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 20lnx = 0 + -4
20lnx = 0 + -4

Combine like terms: 0 + -4 = -4
20lnx = -4

Divide each side by '20nx'.
l = -0.2n-1x-1

Simplifying
l = -0.2n-1x-1

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